5x^2+0x-2=0

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Solution for 5x^2+0x-2=0 equation:



5x^2+0x-2=0
We add all the numbers together, and all the variables
5x^2+x-2=0
a = 5; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·5·(-2)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{41}}{2*5}=\frac{-1-\sqrt{41}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{41}}{2*5}=\frac{-1+\sqrt{41}}{10} $

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